3x^2+6x-1=170

Solution for 3x^2+6x-1=170 equation:

3x^2+6x-1=170

We move all terms to the left:

3x^2+6x-1-(170)=0

We add all the numbers together, and all the variables

3x^2+6x-171=0

a = 3; b = 6; c = -171;
Δ = b2-4ac
Δ = 62-4·3·(-171)
Δ = 2088
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2088}=\sqrt{36*58}=\sqrt{36}*\sqrt{58}=6\sqrt{58}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{58}}{2*3}=\frac{-6-6\sqrt{58}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{58}}{2*3}=\frac{-6+6\sqrt{58}}{6}
$